amide(redirected from Bodroux reaction)
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1. An organic compound, such as acetamide, containing the CONH2 group.
2. The anion of ammonia, NH2- or a compound containing this anion, such as sodium amide, NaNH2.
a·mid′ic (ə-mĭd′ĭk, ă-mĭd′-) adj.
1. (Elements & Compounds) any organic compound containing the functional group -CONH2
2. (Elements & Compounds) (modifier) consisting of, containing, or concerned with the group -CONH2: amide group or radical.
3. (Elements & Compounds) an inorganic compound having the general formula M(NH2)x, where M is a metal atom
[C19: from am(monia) + -ide]
am•ide(ˈæm aɪd, -ɪd)
1. a metallic derivative of ammonia in which the −NH2 group is retained, as potassium amide, KNH2.
2. an organic compound formed from ammonia by replacing a hydrogen atom by an acyl.
a•mid•ic (əˈmɪd ɪk) adj.
A compound containing the radical CONH2.
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|Noun||1.||amide - any organic compound containing the group -CONH2|
acetamide, ethanamide - a colorless solid amide of acetic acid used as a solvent and in the synthesis of organic compounds
acrylamide - a white crystalline amide of propenoic acid can damage the nervous system and is carcinogenic in laboratory animals; "they claimed that acrylamide is produced when certain carbohydrates are baked or fried at high temperatures"
organic compound - any compound of carbon and another element or a radical
peptide - amide combining the amino group of one amino acid with the carboxyl group of another; usually obtained by partial hydrolysis of protein