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Divergent series
(redirected from Summable)

   Also found in: Encyclopedia, Wikipedia 0.01 sec.
(Math.) See Diverging series, under Diverging.

See also: Divergent



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n] is said to be summable [[absolute value of C, [alpha]].
We also show that if two double series are boundedly convergent, then the Cauchy product double series is Cesaro summable and its Cesaro sum is equal to the product of the sums of the given double series.
 
 
 
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