decrescent

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de·cres·cent

 (dĭ-krĕs′ənt)
adj.
Becoming gradually less; waning.

[Latin dēcrēscēns, dēcrēscent-, present participle of dēcrēscere, to decrease; see decrease.]
American Heritage® Dictionary of the English Language, Fifth Edition. Copyright © 2016 by Houghton Mifflin Harcourt Publishing Company. Published by Houghton Mifflin Harcourt Publishing Company. All rights reserved.

decrescent

(dɪˈkrɛsənt)
adj
(Astronomy) (esp of the moon) decreasing; waning
[C17: from Latin dēcrescēns growing less; see decrease]
deˈcrescence n
Collins English Dictionary – Complete and Unabridged, 12th Edition 2014 © HarperCollins Publishers 1991, 1994, 1998, 2000, 2003, 2006, 2007, 2009, 2011, 2014

de•cres•cent

(dɪˈkrɛs ənt)

adj.
waning; diminishing; decreasing.
[1600–10; < Latin dēcrēscent-, s. of dēcrēscēns, present participle of dēcrēscere to decrease; see -ent]
de•cres′cence, n.
Random House Kernerman Webster's College Dictionary, © 2010 K Dictionaries Ltd. Copyright 2005, 1997, 1991 by Random House, Inc. All rights reserved.
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References in periodicals archive
The two largest national producers of this spice, in decrescent order, are the state of Para (North) and Espirito Santo (Southeast), highlighting the municipality of Sao Mateus-ES.
"I am willing to go -10, decrescent. I do not care.
Furthermore, estimate (32) and inequality (33) show that the function V(t, X) is radially unbounded and decrescent, respectively.
A function V(t, x) [greater than or equal to] 0 is said to be decrescent if there exists a function b(r) such that b(0) = 0, b(r) is strictly monotonically increasing in r, and V(t,x) [less than or equal to] b([parallel]x[parallel]), (t,x) [member of] D.
The advantage of less computation complexity is not evident as the observation vector number increases in the PEF, while the decrescent rate of the multiplicational cost error for the two filters reduces more slowly than that of the additional cost error.
If there exists a positive-definite decrescent radially unbounded function V(x, t) [member of] [C.sup.2,1]([R.sup.d] x [[t.sub.0], [infinity]); [R.sub.+]) such that LV(x, t) is negative-definite, then the trivial solution of (15) is stochastically asymptotically stable in the large.
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