duodecillion

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du·o·de·cil·lion

 (do͞o′ō-dĭ-sĭl′yən, dyo͞o′-)
n.
1. The cardinal number equal to 1039.
2. Chiefly British The cardinal number equal to 1072.

[Latin duodecim, twelve; see duodecimal + (m)illion.]

du′o·de·cil′lion adj.
du′o·de·cil′lionth adj.adv. & n.
American Heritage® Dictionary of the English Language, Fifth Edition. Copyright © 2016 by Houghton Mifflin Harcourt Publishing Company. Published by Houghton Mifflin Harcourt Publishing Company. All rights reserved.

duodecillion

(ˌdjuːəʊdɪˈsɪljən)
n
(Units) a name for a number also known as sextilliard and equivalent to 10 to the power 39 in the short scale numerical system
Collins English Dictionary – Complete and Unabridged, 12th Edition 2014 © HarperCollins Publishers 1991, 1994, 1998, 2000, 2003, 2006, 2007, 2009, 2011, 2014

du•o•de•cil•lion

(ˌdu oʊ dɪˈsɪl yən, ˌdyu-)

n., pl. -lions, (as after a numeral) -lion, n.
1. a cardinal number represented in the U.S. by 1 followed by 39 zeros, and in Great Britain by 1 followed by 72 zeros.
adj.
2. amounting to one duodecillion in number.
[1910–15; < Latin duodecim twelve]
du`o•de•cil′lionth, n., adj.
Random House Kernerman Webster's College Dictionary, © 2010 K Dictionaries Ltd. Copyright 2005, 1997, 1991 by Random House, Inc. All rights reserved.
References in periodicals archive
Short scale Long scale billion [10.sup.9] milliard trillion [10.sup.12] billion quadrillion [10.sup.15] billiard quintillion [10.sup.18] trillion sextillion [10.sup.21] trilliard septillion [10.sup.24] quadrillion octillion [10.sup.27] quadrilliard nonillion [10.sup.30] quintillion decillion [10.sup.33] quintilliard undecillion [10.sup.36] sextillion duodecillion [10.sup.39] sextilliard tredecillion [10.sup.42] septillion
This means that the real-life total was 13.5 deviations away from the expected mean, which implies that the odds of getting these numbers simply by chance are about one in 150 duodecillion (150 followed by 39 zeros).
The new protocol can handle one third of a duodecillion addresses; that's 340, 282, 366, 920, 938, 463, 463, 374, 607, 451, 768, 211, 456 for those who like really big numbers.
It turned out to be 1 duodecillion - that is, 1 followed by 39 zeros.
DUODECILLION ([10.sup.39]) = [[[square root of (D/U x One)].sup.([{D + Eighty}/[square root of C]] + I + [L/L] - 1 - One - Nineteen)]
The most economical set I have been able to obtain is <ONE, THREE, FOUR, FIVE, EIGHT, N1NE, TEN, ELEVEN, FOURTEEN, EIGHTEEN, THIRTY, FORTY, ONE DECILLION, ONE DUODECILLION, ONE TREDECILLION> which generates <C,D,E, F,G,H,I,K,L,N,O,R,T,V,Y> as follows:
The shortest number name having two more vowels than consonants is ONE DUODECILLION ONE, and the highest is NINETY-ONE DUODECILLION NINETY-ONE UNDECILLION NINETY-ONE DECILLION NINETY-ONE NONILLION NINETY-ONE OCTILLION NINETY-ONE QUINTILLION NINETY-ONE QUADRILLION NINETY-ONE BILLION NINETY-ONE MILLION NINETY-ONE.
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