conchoidal

(redirected from conchoidally)
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con·choi·dal

 (kŏng-koid′l)
adj.
Of, relating to, or being a surface characterized by smooth, shell-like convexities and concavities, as on fractured obsidian.

[From Greek konkhoeidēs, mussellike : konkho-, concho- + -oeidēs, -oid.]

con·choi′dal·ly adv.

conchoidal

(kɒŋˈkɔɪdəl)
adj
1. (Geological Science) (of the fracture of minerals and rocks) having smooth shell-shaped convex and concave surfaces
2. (Geological Science) (of minerals and rocks, such as flint) having such a fracture
conˈchoidally adv

con•choi•dal

(kɒŋˈkɔɪd l)

adj.
denoting a fracture shape whose surface resembles the inside of a clamshell, characteristic of certain minerals.
[1660–70]
con•choi′dal•ly, adv.
References in periodicals archive ?
In outcrop, the shale appears to be homogeneous massive claystone; it breaks conchoidally and displays no obvious bedding.