(redirected from Countable set)
Also found in: Thesaurus, Encyclopedia, Wikipedia.


1. Capable of being counted: countable items; countable sins.
2. Mathematics Capable of being put into a one-to-one correspondence with the positive integers.

count′a·bil′i·ty n.
count′a·bly adv.
American Heritage® Dictionary of the English Language, Fifth Edition. Copyright © 2016 by Houghton Mifflin Harcourt Publishing Company. Published by Houghton Mifflin Harcourt Publishing Company. All rights reserved.


1. (Grammar) grammar the fact of being countable
2. (Mathematics) maths denumerability
Collins English Dictionary – Complete and Unabridged, 12th Edition 2014 © HarperCollins Publishers 1991, 1994, 1998, 2000, 2003, 2006, 2007, 2009, 2011, 2014
References in periodicals archive ?
There exists a countable set E in [epsilon] such that A = [E.sup.[perpendicular to].sub.w] + A where,
For each d [member of] D, define A(d) to be a countable set of balls with center at d, with radius r(d, n) [down arrow] 0 when n [right arrow] [infinity] such that P([partial derivative][B.sub.r(d,n)](d)) = 0, for n = 1,2, ..., where x [member of] D, [B.sub.r](x) = {y | d(y, x) < r}, and [partial derivative]F denotes the boundary of given set F.
We shall show that the countable set {d.[x.sub.o]; d [member of] D} is dense in [OMEGA]* in the weak topology.
Let B = {[u.sub.n]} [subset] PC(J, E) be a bounded and countable set. Then [alpha](B(t)) is Lebesgue integral on J, and
Let us consider a qso V (5) defined on countable set X.
(2) except for a countable set of values [alpha](p, A), one has
The symmetry of KGE on the chosen orbit discloses existence of a new countable set of the modal amplitudes oscillating with the same cut-off frequency.
Then X-C is [zeta]-open and hence for every x [member of] X - C, there exists an open set U containing x and a countable set B such that U - B [subset not equal to] sInt(X - C) [subset not equal to] X - [Cl.sub.T] (C).
Then, the set of all jump discontinuity points of f is at most a countable set in R.
First, if sampling a function f on the countable set X leads to unique and stable reconstruction of f, then when does sampling on the set X' = {[x.sub.j] + [[delta].sub.j] : j [member of] J} also lead to unique and stable reconstruction?
Since B is separable we can find a countable set {[h.sub.n]} in B such that [MATHEMATICAL EXPRESSION NOT REPRODUCIBLE IN ASCII] for all nand the subspace H generated by {[h.sub.n]} is dense in B.